15x^2-128x+256=0

Solution for 15x^2-128x+256=0 equation:

15x^2-128x+256=0

a = 15; b = -128; c = +256;
Δ = b2-4ac
Δ = -1282-4·15·256
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-32}{2*15}=\frac{96}{30}
=3+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+32}{2*15}=\frac{160}{30}
=5+1/3
$